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510_Physics ProblemsTechnical Physics

# 510_Physics ProblemsTechnical Physics - 512 P17.41 Sound...

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512 Sound Waves P17.41 ′= F H G I K J ff v vv s 485 512 340 340 9 80 = −− F H G I K J . t fall bg 485 340 485 9 80 512 340 512 485 485 340 980 193 af di += = F H G I K J = . . . t t f f s dg t f 1 2 1 2 18 3 == . m : t return s 18 3 340 00538 . . The fork continues to fall while the sound returns. tt t t f total fall return total total fall 2 s s s m =+ = + = 1985 1 2 19 3 .. . . P17.42 (a) v ⋅° −° = 331 0 6 10 325 ms m sC C m s a f . (b) Approaching the bell, the athlete hears a frequency of + F H G I K J v O After passing the bell, she hears a lower frequency of ′′ = +− F H G I K J v O The ratio is ′′ = + = f f O O 5 6 which gives 6 6 5 5 vv vv oo −= + or v v O = 11 325 11 29 5 . *P17.43 (a) Sound moves upwind with speed 343 15 ms. Crests pass a stationary upwind point at frequency 900 Hz. Then λ = v f 328 900 0364 s m . (b) By similar logic, + = v f 343 15 900 0398 a f s m . (c) The source is moving through the air at 15 m/s toward the observer. The observer is
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