511_Physics ProblemsTechnical Physics

511_Physics ProblemsTechnical Physics - Chapter 17*P17.44...

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Chapter 17 513 *P17.44 The half-angle of the cone of the shock wave is θ where θ = F H G I K J = F H G I K J = ° sin sin . . 1 1 1 1 5 41 8 v v sound source . As shown in the sketch, the angle between the direction of propagation of the shock wave and the direction of the plane’s velocity is φ θ = °− = °− °= ° 90 90 41 8 48 2 . . . φ v shock v plane θ FIG. P17.44 P17.45 The half angle of the shock wave cone is given by sin θ = v v S light . v v S = = × ° = × light m s m s sin . sin . . θ 2 25 10 53 0 2 82 10 8 8 a f P17.46 θ = = = °
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