525_Physics ProblemsTechnical Physics

# 525_Physics ProblemsTechnical Physics - Chapter 18 P18.6 FG...

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Chapter 18 527 P18.6 2 2 00 AA cos φ F H G I K J = so φπ 2 1 2 60 0 3 1 = F H G I K J = cos . Thus, the phase difference is π = 120 2 3 This phase difference results if the time delay is T fv 3 1 33 == λ Time delay 300 0500 . . m 32 .00 ±ms s bg P18.7 (a) If the end is fixed, there is inversion of the pulse upon reflection. Thus, when they meet, they cancel and the amplitude is zero . (b) If the end is free, there is no inversion on reflection. When they meet, the amplitude is 2 2 0 150 0 300 A .. m m af . P18.8 (a) x = +−=−= 9 00 4 00 3 00 13 3 00 0 606 ... m The wavelength is = v f 343 300 114 ms Hz m . Thus, x 0606 0530 . . . o f a w a v e , or 2 0 530 3 33 a f rad (b) For destructive interference, we want ∆∆ x f x v . where x is a constant in this set up. f v x = 2 343 20606 283 . a f Hz P18.9 We suppose the man’s ears are at the same level as the lower speaker. Sound from the upper speaker is delayed by traveling the extra distance
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