530_Physics ProblemsTechnical Physics

530_Physics ProblemsTechnical Physics - 532 Superposition...

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532 Superposition and Standing Waves Section 18.3 Standing Waves in a String Fixed at Both Ends P18.19 L = 30 0 . m; µ 900 10 3 . k g m ; T = 20 0 . N ; f v L 1 2 = where v T = F H G I K J = 12 47 1 . ms so f 1 47 1 60 0 0786 == . . H z ff 21 5 7 H z 31 32 3 6 H z 41 43 1 4 H z *P18.20 The tension in the string is T 49 8 3 9 2 kg m s N 2 bg ej .. Its linear density is × m L 81 0 16 10 3 3 kg 5 m kg m . and the wave speed on the string is v T × = 39 2 10 156 5 3 . . N 1.6 kg m ms In its fundamental mode of vibration, we have λ = 22 5 1 0 L m m af Thus, f v = 156 5 10 15 7 . . m Hz P18.21 (a) Let n be the number of nodes in the standing wave resulting from the 25.0-kg mass. Then n + 1 is the number of nodes for the standing wave resulting from the 16.0-kg mass. For
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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