Chapter 18535P18.28λGGvf==20350. maf; AAALvf2LLLffLLffGAGGAGGGA−=−FHGIKJ=−FHGIKJFHGIKJ=10350139244000382..m mafThus, AG=−=0 038 20 3500 038 20 312mm,or the finger should be placed 31 2cmfromthebridge.LvffTA212µ; dLdTfTAA=4; dLLdTTAA=12dTTdLLAA−=220600382384%...cm35.0cmafP18.29In the fundamental mode, the string above the rod has onlytwo nodes, at A and B, with an anti-node halfway between Aand B. Thus,θ2ABLcosor =2Lcos.Since the fundamental frequency is f, the wave speed in thissegment of string isvfLf2cos.Also, vTTmABTLm=µθcoswhere Tis the tension in this part of the string. Thus,2LfTLmcoscosθθ=or 42LfTLmcoscos=and the mass of string above the rod is:mTLf=cos42[Equation 1]LMABTFMgFIG. P18.29Now, consider the tension in the string. The light rod would rotate about point P if the string exerted
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .