535_Physics ProblemsTechnical Physics

535_Physics ProblemsTechnical Physics - Chapter 18 Section...

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Chapter 18 537 Section 18.4 Resonance P18.32 The natural frequency is f T g L = = = = 1 1 2 1 2 9 80 2 00 0 352 π π . . . m s m Hz 2 . The big brother must push at this same frequency of 0 352 . Hz to produce resonance. P18.33 (a) The wave speed is v = = 9 15 3 66 . . m 2.50 s m s (b) From the figure, there are antinodes at both ends of the pond, so the distance between adjacent antinodes is d AA m = = λ 2 9 15 . , and the wavelength is λ = 18 3 . m The frequency is then f v = = = λ 3 66 18 3 0 200 . . . m s m Hz We have assumed the wave speed is the same for all wavelengths. P18.34 The wave speed is v gd = = = 9 80 36 1 18 8 . . . m s m m s 2 e j a f The bay has one end open and one closed. Its simplest resonance is with a node of horizontal velocity, which is also an antinode of vertical displacement, at the head of the bay and an antinode of velocity, which is a node of displacement, at the mouth. The vibration of the water in the bay is
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