536_Physics ProblemsTechnical Physics

536_Physics ProblemsTechnical Physics - 538 Superposition...

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538 Superposition and Standing Waves Section 18.5 Standing Waves in Air Columns P18.36 d AA m = 0320 .; λ = 0640 . m (a) f v == 531 Hz (b) = 00850 m ; d AA mm = 42 5 . P18.37 (a) For the fundamental mode in a closed pipe, = 4 L , as in the diagram. But vf = , therefore L v f = 4 So, L 343 4240 0357 1 ms s m ej . (b) For an open pipe, = 2 L , as in the diagram. So, L v f = 2 343 2240 0715 1 s m . /4 L N A /2 A A N FIG. P18.37 P18.38 The wavelength is = v f 343 131 261.6 s m . so the length of the open pipe vibrating in its simplest (A-N-A) mode is d A to A m 1 2 0656 . A closed pipe has (N-A) for its simplest resonance, (N-A-N-A) for the second, and (N-A-N-A-N-A) for the third. Here, the pipe length is
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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