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536_Physics ProblemsTechnical Physics

# 536_Physics ProblemsTechnical Physics - 538 Superposition...

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538 Superposition and Standing Waves Section 18.5 Standing Waves in Air Columns P18.36 d AA m = 0 320 . ; λ = 0 640 . m (a) f v = = λ 531 Hz (b) λ = 0 085 0 . m; d AA mm = 42 5 . P18.37 (a) For the fundamental mode in a closed pipe, λ = 4 L , as in the diagram. But v f = λ , therefore L v f = 4 So, L = = 343 4 240 0 357 1 m s s m e j . (b) For an open pipe, λ = 2 L , as in the diagram. So, L v f = = = 2 343 2 240 0 715 1 m s s m e j . λ /4 L N A λ /2 A A N FIG. P18.37 P18.38 The wavelength is λ = = = v f 343 1 31 m s 261.6 s m . so the length of the open pipe vibrating in its simplest (A-N-A) mode is d A to A m = = 1 2 0 656 λ . A closed pipe has (N-A) for its simplest resonance, (N-A-N-A) for the second, and (N-A-N-A-N-A) for the third.
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