542_Physics ProblemsTechnical Physics

542_Physics ProblemsTechnical Physics - 544 P18.60...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
544 Superposition and Standing Waves P18.60 v = × = 48 0 2 00 480 10 141 3 .. . af ms d NN m = 100 .; λ = 200 . m ; f v == 70 7 . H z a a v f = 343 70 7 485 Hz m . . P18.61 Call L the depth of the well and v the speed of sound. Then for some integer n Ln n v f n =− = 21 4 4 3 4 3 4515 1 1 1 a f a f bg ej s . and for the next resonance n v f n =+ = + = + 1 4 4 3 4 3 4600 2 2 1 a f a f s . Thus, 3 4 3 3 4 3 11 nn = + −− s s and we require an integer solution to 60 0 51 5 + = The equation gives n 111 5 17 656 . . , so the best fitting integer is n = 7. Then L = = 27 1 343 21 6 1 s m . . and L = + = 21 4 1 s m . . suggest the best value for the depth of the well is 21 5 . m. P18.62 The second standing wave mode of the air in the pipe reads ANAN, with
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

Ask a homework question - tutors are online