543_Physics ProblemsTechnical Physics

543_Physics ProblemsTechnical Physics - Chapter 18 P18.63...

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Chapter 18 545 P18.63 (a) Since the first node is at the weld, the wavelength in the thin wire is 2 L or 80.0 cm. The frequency and tension are the same in both sections, so f L T == × = 1 2 1 20400 460 200 10 59 9 3 µ . . . . a f Hz . (b) As the thick wire is twice the diameter, the linear density is 4 times that of the thin wire. ′= 800 . gm so ′ = L f T 1 2 L N M O Q P × = L 1 25 99 800 10 20 0 3 af a f . . . . cm half the length of the thin wire. P18.64 (a) For the block: FTM g x =− ° = sin . 30 0 0 so TM g M g = sin . 30 0 1 2 . (b) The length of the section of string parallel to the incline is h h sin . 30 0 2 ° = . The total length of the string is then 3 h . FIG. P18.64 (c) The mass per unit length of the string is = m h 3 (d) The speed of waves in the string is v T Mg h m Mgh m F H G I K J F H
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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