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553_Physics ProblemsTechnical Physics

553_Physics ProblemsTechnical Physics - Chapter 19...

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Chapter 19 555 P19.20 (a),(b) The material would expand by L L T i = α , L L T F A Y L L Y T i i = = = = × × ° ° = × α α , but instead feels stress N m C C N m . This will not break concrete. 2 2 7 00 10 12 0 10 30 0 2 52 10 9 6 1 6 . . . . e j a f a f P19.21 (a) V V T V T V T t t t i = = = × × ° ° β β β α Al Al Al 3 C cm C 3 9 00 10 0 720 10 2 000 60 0 4 4 1 b g e j e j a f . . . V = 99 4 . cm 3 overflows. (b) The whole new volume of turpentine is 2 000 9 00 10 2 000 60 0 2 108 4 1 cm C cm C cm 3 3 3 + × ° ° = . . e j a f so the fraction lost is 99 4 2 108 4 71 10 2 . . cm cm 3 3 = × and this fraction of the cylinder’s depth will be empty upon cooling: 4 71 10 20 0 0 943 2 . . . × = cm cm a f . *P19.22 The volume of the sphere is V r Pb 3 cm cm = = = 4 3 4 3 2 33 5 3 3 π π a f . . The amount of mercury overflowing is overflow Hg Pb glass Hg Hg Pb Pb glass glass = + = + V V V V V V T β
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