Chapter 19567P19.64(a)From PVnRT=, the volume is:VnRPT=FHGIKJTherefore, when pressure is held constant,dVdTnRPVT==Thus,β≡FHGIKJ=FHGIKJ′11VdVdTVVT, or =1T(b)At T=° =0273CK, this predicts×−−1273366 1031KK.Experimental values are:HeK=×3665 10.and airK367 10.They agree within 0.06% and 0.2%, respectively.P19.65For each gas alone, PNkTV11=and PV22=and PV33=, etc.For all gasesPVNNNkTNNN kTPV112233123++=++=………bgandAlso, VVVV====…, therefore PP P P=++….P19.66(a)Using the Periodic Table, we find the molecular masses of the air components to beMN u2=28 01.,MO u2=32 00MAruaf=39 95.and MCOu2=44 01..Thus, the number of moles of each gas in the sample isnnnnON
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .