Chapter 20581P20.10(a)fmgh mcTbgbg=∆0600 300 1098050041863000092407602583......;.afejejbgaf×=⋅°=°=°−kgm smJcalg calgCCC2∆∆TTT(b)No . Both the change in potential energy and the heat absorbed are proportional to themass; hence, the mass cancels in the energy relation.*P20.11We do not know whether the aluminum will rise or drop in temperature. The energy the water canabsorb in rising to 26°C is mc T∆=°°=02566279. kgJkg CCJ . The energy the copper can putout in dropping to 26°mc T°0 1387742 864. kgJkg CCJ . Since 6 2792 864J J>, the finaltemperature is less than 26°C. We can write QQhc=−asQTTTTffffffwaterAlCukg Jkg CC kgJkg CCkg Jkg CCCCC++=°−°+°−°+°=+−°+−°=00 25200 4900260138710001 046 520 9303609 36038 73 87001 445 23416023 6...diP20.12coldhotmcTT mcTTmc mc T mc mc TmcT mcTm cmcmc Tmc T mcT
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .