582 Heat and the First Law of Thermodynamics*P20.14Vessel one contains oxygen according to PVnRT=:nPVRTc==××⋅=−1 75 1 013 1016 8 108314119453.....PamNm mol K 300 Kmol3ej.Vessel two contains this much oxygen:nh==−2 25 1 013 10 22 4 1083144501365...afmolmol.(a)The gas comes to an equilibrium temperature according tomc Tmc TnMcTcfhf∆∆afdicoldhotK K=−−+−=3004500The molar mass Mand specific heat divide out:1 194358 21 365614 10972 3380.TTTfff−+−=KK2.559K(b)The pressure of the whole sample in its final state isPnRTV+×=×=−255916 810206 1020435..mol 8.314 J 380 Kmol K 22.4mPaatm3.Section 20.3Latent HeatP20.15The heat needed is the sum of the following terms:Qneededheat to reach melting pointheat to meltheat to reach melting pointheat to vaporizeheat to reach 110 C
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .