This preview shows page 1. Sign up to view the full content.
Chapter 20
593
P20.57
Qm
cT V
cT
==
∆∆
ρ
bg
so that when a constant temperature difference
∆
T
is maintained,
the rate of adding energy to the liquid is
P
F
H
G
I
K
J
=
dQ
dt
dV
dt
R
ρρ
and the specific heat of the liquid is
c
RT
=
∆
.
P20.58
(a)
Work done by the gas is the negative of the area under the
PV
curve
WP
V
V
PV
i
i
i
ii
=−
−
F
H
G
I
K
J
=+
22
.
(b)
In this case the area under the curve is
d
V
z
. Since the
process is isothermal,
PV
P
V
nRT
i
i
i
F
H
G
I
K
J
=
4
4
and
W
dV
V
V
V
V
V
i
i
i
i
F
H
G
I
K
J
F
H
G
I
K
J
=
z
4
4
4
ln
ln
139
.
FIG. P20.58
(c)
The area under the curve is 0 and
W
=
0.
P20.59
Call the initial pressure
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .
 Fall '11
 Staff
 Physics, Energy, Work, Heat

Click to edit the document details