Chapter 20593P20.57QmcT VcT==∆∆ρbgso that when a constant temperature difference ∆Tis maintained,the rate of adding energy to the liquid is PFHGIKJ=dQdtdVdtRρρand the specific heat of the liquid is cRT=∆.P20.58(a)Work done by the gas is the negative of the area under thePVcurveWPVVPViiiii=−−FHGIKJ=+22.(b)In this case the area under the curve is dVz. Since theprocess is isothermal,PVPVnRTiiiFHGIKJ=44andWdVVVVVViiiiFHGIKJFHGIKJ=z444lnln139.FIG. P20.58(c)The area under the curve is 0 and W=0.P20.59Call the initial pressure
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .