602_Physics ProblemsTechnical Physics

602_Physics ProblemsTechnical Physics - 604 P21.8 The...

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604 The Kinetic Theory of Gases P21.8 v kT m B = 3 v v M M v O He He O O ms == = 400 32 0 1 800 1350 477 . .. . P21.9 (a) Kk T B × = × −− 3 2 3 2 1 3 81 0 4 2 3 8 7 61 0 23 21 JK K J ej a f (b) Km v rms × 1 2 876 10 22 1 . J so v m rms = × 175 10 20 J (1) For helium, m = × 602 10 664 10 23 24 . . . gmo l molecules mol l e cu l e m 27 k g m o l e c u l e Similarly for argon, m = × 39 9 663 10 23 23 . . . l molecules mol l e l e m 26 k g m o l e c u l e Substituting in (1) above, we find for helium, v rms = 162 k m s and for argon, v rms = 514 m s P21.10 (a) PV nRT Nmv 2 3 The total translational kinetic energy is Nmv E 2 2 = trans : EP V trans kJ ×× ×= 3 2 3 2 3 00 1 013 10 5 00 10 2 28 53 . . e j (b) mv RT N B 2 23 21 2 3 2 3 2 38314 300 2 6 02 10 621 10 === × A J . . . af
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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