606 The Kinetic Theory of GasesP21.16(a)Consider heating it at constant pressure. Oxygen and nitrogen are diatomic, so CRP=72QnC T nRTPVTTQP===FHGIKJ=×=∆∆∆7272721 013 101003001001185..NmmKK kJ23ejejaf(b)Umgyg=mUgyg×=×118 10200603 1053...J9.80 m smkg2*P21.17(a)We assume that the bulb does not expand. Then this is a constant-volume heating process.The quantity of the gas is nPVRTii=. The energy input is QtnCTVPso∆∆∆TtnCtRTPVCViiV.The final temperature is TT TTtRfii=+ =+FHGIKJ∆∆1.The final pressure is PPTTPtRfii+FHGIKJ1∆.(b)Pf=+⋅⋅×FHGIKJ=1136012 53atmJ 4 s 8.314 J m 3 mol Ks mol K 1.013 10 N 40.05 mJatm25...πP21.18(a)CRV⋅FHGIKJ=⋅=⋅525283147190 719...JmolKmol0.028 9 kgJ kg KkJ kg Kbg(b)mMnMPVRTFHGIKJm=×⋅FHGGIKJJ=00289200 1030008113
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .