{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

604_Physics ProblemsTechnical Physics

604_Physics ProblemsTechnical Physics - 606 P21.16 The...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
606 The Kinetic Theory of Gases P21.16 (a) Consider heating it at constant pressure. Oxygen and nitrogen are diatomic, so C R P = 7 2 Q nC T nR T PV T T Q P = = = F H G I K J = × = 7 2 7 2 7 2 1 013 10 100 300 1 00 118 5 . . N m m K K kJ 2 3 e je j a f (b) U mgy g = m U gy g = = × = × 1 18 10 2 00 6 03 10 5 3 . . . J 9.80 m s m kg 2 e j *P21.17 (a) We assume that the bulb does not expand. Then this is a constant-volume heating process. The quantity of the gas is n PV RT i i = . The energy input is Q t nC T V = = P so T t nC tRT PVC V i i V = = P P . The final temperature is T T T T tR PVC f i i i V = + = + F H G I K J 1 P . The final pressure is P P T T P tR PVC f i f i i i V = = + F H G I K J 1 P . (b) P f = + × F H G I K J = 1 1 3 60 12 5 1 18 3 atm J 4 s 8.314 J m 3 mol K s mol K 1.013 10 N 4 0.05 m J atm 2 5 . . . π a f P21.18 (a) C R V = = F H G I K J = = 5 2 5 2 8 314 1 00 719 0 719 . . . J mol K mol 0.028 9 kg J kg K kJ kg K b g (b) m Mn M PV RT = = F H G I K J m = × F H G G I K J J = 0 028 9
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}