610_Physics ProblemsTechnical Physics

610_Physics ProblemsTechnical Physics - 612 The Kinetic...

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612 The Kinetic Theory of Gases (e) In AB , Qn C T n R T T n R T AB V i i i == F H G I K J −= 5 2 35 0 0 bg af . Q PV nRT P V T T C T n R T T n R T BC CC C i i i C i CA P i i i = = = F H G I K J 0 219 7 2 417 as this process is abiabatic so .. . For the whole cycle, QQ Q Q n R T n R T EQ W WQ n R T P V ABCA AB BC CA i i ABCA ABCA ABCA ABCA ABCA i i i =++= = + =− = − 500 417 0830 0 . int P21.31 (a) The work done on the gas is WP d V ab V V a b z . For the isothermal process, Wn R T V dV R T V V nRT V V ab a V V ab a b a a b a b F H G I K J F H G I K J = F H G I K J z 1 ln ln . Thus, W ab =⋅ 500 293 100 .l n . mol 8.314 J mol K K a f W ab = 28 0 . k J. FIG. P21.31 (b) For the adiabatic process, we must first find the final temperature, T b . Since air consists primarily of diatomic molecules, we shall use γ air = 140 . and C R V , air Jmo lK = 5 2 58314 2 20 8
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