611_Physics ProblemsTechnical Physics

611_Physics ProblemsTechnical Physics - 613 Chapter 21 (c)...

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Chapter 21 613 (c) For the isothermal process, we have PV bb aa ′′ = . Thus, PP V V ba a b = F H G I K J == 100 .. atm 10.0 atm a f . For the adiabatic process, we have b b γ = . Thus, V V a b = F H G I K J 251 1.40 atm 10.0 atm a f . P21.32 We suppose the air plus burnt gasoline behaves like a diatomic ideal gas. We find its final absolute pressure: 21 0 400 21 0 1 14 75 . atm 50.0 cm cm atm 1 8 atm 33 ej = = F H G I K J = P P f f Now Q = 0 and WE n C T T Vf i int di ∴= = Wn R T n R T P V P V fi f f i i 5 2 5 2 5 2 FIG. P21.32 W W =− × F H G I K J 5 2 114 210 1 10 150
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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