613_Physics ProblemsTechnical Physics

613_Physics ProblemsTechnical Physics - Chapter 21 P21.35...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 21 615 P21.35 Rotational Kinetic Energy = 1 2 2 I ω Im r = 2 2 , m =×× 35 0 1 67 10 27 .. k g , r = 10 10 m I 117 10 45 . k g m 2 200 10 12 1 s ∴= = × KI rot J 1 2 233 10 22 1 . Cl Cl FIG. P21.35 Section 21.5 The Boltzmann Distribution Law Section 21.6 Distribution of Molecular Speeds P21.36 (a) The ratio of the number at higher energy to the number at lower energy is e EkT B −∆ where E is the energy difference. Here, E = × F H G I K J 10 2 160 10 163 10 19 18 . . . eV J 1 eV J af and at 0°C, kT B = × −− 1 3 81 0 2 7 3 3 7 71 0 23 21 JK K J ej a f . Since this is much less than the excitation energy, nearly all the atoms will be in the ground state and the number excited is
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

Ask a homework question - tutors are online