618_Physics ProblemsTechnical Physics

# 618_Physics ProblemsTechnical Physics - 620 P21.51 The...

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620 The Kinetic Theory of Gases P21.51 (a) P f = 100 kPa T f = 400 K V nRT P f f f == × 200 400 100 10 00665 665 3 . .. mol 8.314 J mol K K Pa m L 3 bg af ∆∆ En R T int mol J mol K K kJ = 350 350200 8314 100 582 . . . a f a f a f WP Vn R T =− = − 166 . mol J mol K K kJ QE W = + = int kJ kJ kJ 748 . (b) T f = 400 K VV nRT P fi i i = × 300 100 10 00499 499 3 . mol 8.314 J mol K K Pa L 3 PP T T f i = F H G I K J = F H G I K J = 100 400 133 kPa K 300 K kPa d V = z 0 since V = constant E int kJ = . as in part (a) W = = int kJ kJ 0 (c) P f = 120 kPa T f = 300 K P P i f = F H G I K J = F H G I K J = 49 9 41 6 L 100 kPa 120 kPa L R T int 0 . a f since T = constant d V n R T dV V nRT V V nRT P P W W i V V i f i i i f i f F H G I K J F H G I K J F H G I K J =+ = −= zz ln ln l n 100 909 09 1 0 9 0 9 mol J mol K K kPa 120 kPa J J J int a f a f (d) P f = 120 kPa γ + = + C C CR C RR R P V V V 450 9 7 . . . . PV f f i i γγ = : so P P i f = F H G I K J = F H G I K J = 1 79 49 9 43 3 L 100 kPa 120 kPa L TT R T Q WQE ff ii = F H G I K J = F H G I K J F H G I K J = = = =− + = + 300 120 43 3 312 3 50 3 50 2 00
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