626_Physics ProblemsTechnical Physics

# 626_Physics ProblemsTechnical Physics - 628 P21.67 The...

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628 The Kinetic Theory of Gases P21.67 (a) n PV RT == ×× = 1013 10 500 10 8314 300 0203 53 .. . . Pa m Jmo lK K mol 3 ej e j bg af (b) TT P P BA B A = F H G I K J = F H G I K J = 300 100 900 K K . . VV T T CB CA C A = F H G I K J = F H G I K J = 900 500 150 K L 900 300 L FIG. P21.67 (c) En R T AA int, mol J mol K K J = 3 2 3 2 0 203 8 314 300 760 a f a f EE n R T BC B int, int, mol J mol K K kJ = = 3 2 3 2 0 203 8 314 900 2 28 . a f a f (d) P (atm) V (L) T (K) E int (kJ) A 1.00 5.00 300 0.760 B 3.00 5.00 900 2.28 C 1.00 15.00 900 2.28 (e) For the process AB , lock the piston in place and put the cylinder into an oven at 900 K. For BC , keep the sample in the oven while gradually letting the gas expand to lift a load on the piston as far as it can. For CA , carry the cylinder back into the room at 300 K and let the gas cool without touching the piston. (f) For AB : W = 0 E int int, int, kJ kJ =−= = 2 28 0 760 1 52 . a f QE W =− = int kJ 152 . For BC : E int = 0 , Wn R T V V B C B F H G I K J ln W W = − = 0 203
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