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633_Physics ProblemsTechnical Physics

# 633_Physics ProblemsTechnical Physics - Chapter 22*P22.5(a...

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Chapter 22 635 *P22.5 (a) The input energy each hour is 7 89 10 2 500 60 1 18 10 3 9 . . × = × J revolution rev min min 1 h J h e j b g implying fuel input 1 18 10 1 29 4 9 . . × × F H G I K J = J h L 4.03 10 J L h 7 e j (b) Q W Q h c = + eng . For a continuous-transfer process we may divide by time to have Q t W t Q t W t Q t Q t h c h c = + = = = × × F H G I K J = × = × F H G I K J = eng eng eng Useful power output J revolution J revolution 1 min min 60 s W W 1 hp 746 W hp 7 89 10 4 58 10 2 500 rev 1 1 38 10 1 38 10 185 3 3 5 5 . . . . P (c) P P eng eng J s rev 60 s rev 2 rad N m = = = × F H G I K J = τω τ ω π 1 38 10 2 500 1 527 5 . b g (d) Q t c = × F H G I K J = × 4 58 10 2 500 1 91 10 3 5 . . J revolution rev 60 s W P22.6 The heat to melt 15.0 g of Hg is Q mL c f = = × × = 15 10 1 18 10 177 3 4 kg J kg J e je j . The energy absorbed to freeze 1.00 g of aluminum is Q mL h f =
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