642 Heat Engines, Entropy, and the Second Law of ThermodynamicsFor the isothermal process CD→:∆∆EnCTVint==0and QWnRTVVDC=−=FHGIKJ=⋅FHGIKJln.ln...23454915 024 0502mol 8.314 J mol KKkJbgaf.Finally, for the adiabatic process DA→:Q=0∆CTTVA Dintmol32J mol KKkJ=⋅LNMOQP−=+bgaf2 348 314720 5494 98...and WQE=− += +∆intkJkJ0498498.ProcessQ(kJ)W(kJ)∆Eint(kJ)AB→+6.58–6.580BC→0–4.98–4.98→–5.02+5.020→0+4.98+4.98ABCDA+1.56–1.560The work done by the engine is the negative of the work input. The output work Wengisgiven by the work column in the table with all signs reversed.(c)eWQWQhABCD−→engkJ6.58 kJ1560237..or 23 7%.eTTcch=− =−=11549720.or 23 7%.P22.23COPrefrigaf=TTc∆27030 0900
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .