Chapter 22643P22.26COPCOPCarnot cycle=0100.orQWQWhh=FHGIKJ=FHGIKJ0 1000 1001..Carnot cycleCarnot efficiencyQWTTThhhc=−FHGIKJ=−FHGIKJ=293268117.K293 KKFIG. P22.26Thus, .joules of energy enter the room by heat for each joule of work done.P22.27COPCarnot refrigaf====TTQWcc∆40028900138..∴=W72 2. J per 1 J energy removed by heat.P22.28A Carnot refrigerator runs on minimum power.For it: QTQThhcc=so QtTThhcc=.Solving part (b) first:(b)QtQtTThc=FHGIKJ=FHGIKJ=×FHGIKJ=800298873 1012436.MJ hK273 KJhh3 600 skWbgej(a)WtQtQt=−=−×=800 1036002046..kW±shWP22.29eWQh0350.WQh=.QWQ=+QQch=0650.COP refrigerator=QWQQh186...*P22.30To have the same efficiencies as engines, 11−=−TTTTcphpcrhrthe pump and refrigerator must operate
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .