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644_Physics ProblemsTechnical Physics

# 644_Physics ProblemsTechnical Physics - 646 Heat Engines...

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646 Heat Engines, Entropy, and the Second Law of Thermodynamics For the entire cycle, E int, net J = + = 162 149 246 65 0 0 . . The net work is W Q eng net J J J J J J = − + + + = = + + = 162 0 246 0 84 3 0 149 0 65 0 84 3 . . . The tables look like: State T (K) P (kPa) V (cm 3 ) E int (J) A 293 100 500 125 B 673 1 840 62.5 287 C 1 023 2 790 62.5 436 D 445 152 500 190 A 293 100 500 125 Process Q (J) output W (J) E int (J) AB 0 –162 162 BC 149 0 149 CD 0 246 –246 DA –65.0 0 –65.0 ABCDA 84.3 84.3 0 (c) The input energy is Q h = 149 J , the waste is Q c = 65 0 . J , and W eng J = 84 3 . . (d) The efficiency is: e W Q h = = = eng J 149 J 84 3 0 565 . . . (e) Let
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