644_Physics ProblemsTechnical Physics

644_Physics ProblemsTechnical Physics - 646 Heat Engines,...

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646 Heat Engines, Entropy, and the Second Law of Thermodynamics For the entire cycle, E int, net J =+ = 162 149 246 65 0 0 . . The net work is W Q eng net J J J J J =− + + + = +− = 162 0 246 0 84 3 01 4 9 06 5 0 8 4 3 . .. The tables look like: State T (K) P (kPa) V (cm 3 ) E int (J) A 293 100 500 125 B 673 1 840 62.5 287 C 1 023 2 790 62.5 436 D 445 152 500 190 A 293 100 500 125 Process Q (J) output W (J) E int (J) AB 0 –162 162 BC 149 0 149 CD 0 246 –246 DA –65.0 0 –65.0 ABCDA 84.3 84.3 0 (c) The input energy is Q h = 149 J , the waste is Q c = 65 0 . J , and W eng J = 84 3 . . (d) The efficiency is: e W Q h === eng J 149 J 84 3
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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