653_Physics ProblemsTechnical Physics

653_Physics ProblemsTechnical Physics - Chapter 22 P22.60...

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Chapter 22 655 P22.60 e T T W Q c c hh W t Q t h =− = = 1 eng eng Q t T TT h T T h hc c h = = P 1 ej Q t Q t T ch c ∆∆ = F H G I K J −= Qm c T c =∆ , where c is the specific heat of water. Therefore, Q t m t cT T c c = F H G I K J = and m t T c T c = bg P22.61 (a) 35 0 5 9 35 0 32 0 1 67 273 15 274 82 .. . . °= + = FC K K af a f 98 6 5 9 98 6 32 0 37 0 273 15 310 15 453 6 1 00 453 6 310 15 274 82 54 86 453 6 1 00 310 15 274 82 310 15 51 67 54 86 51 67 3 19 274.82 310 15 . . . l n . . . . . ... . + = == × = F H G I K J = =− =−= zz K K g cal g K cal K cal K cal K ice water body body system a f b g a f S dQ T dT T S Q T S (b) 453 6 1 274 82 70 0 10 1 310 15 3 . . a f FF × Thus, 70 0 0 453 6 10 70 0 310 15 0 453 6 274 82 10 33 . . . . = + × a f T F and T F ° = ° 30992 3677 9819
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