Chapter 22659The work output in the isothermal expansion isWPdVnRT V dVnRTVVnRTnRTiCiiCiCiii===FHGIKJ−FHGIKJzz−−11313lnlnlnγγγbgejThis is also the input heat, so the entropy change is∆SQTnR−FHGIKJ13lnSinceCCCRPVV+we have−=1CRV, CRV=−1andCRP=−1Then the result is∆SnCP=ln3(b)The pair of processes considered here carry the gas from the initial state in Problem 66 to thefinal state there. Entropy is a function of state. Entropy change does not depend on path.Therefore the entropy change in Problem 66 equals ∆∆SSisothermaladiabatic+in this problem.Since ∆Sadiabatic=0, the answers to Problems 66 and 67 (a) must be the same.P22.68Simply evaluate the maximum (Carnot) efficiency.
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .