665_Physics ProblemsTechnical Physics

665_Physics ProblemsTechnical Physics - Chapter 23 F 10.0...

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Chapter 23 5 P23.2 (a) N = F H G I K J × F H G I K J F H G I K J 10 0 6 02 10 47 2 62 10 23 24 . .. grams 107.87 grams mol atoms mol electrons atom (b) # . . electrons added C 1.60 10 C electron == × × Q e 100 10 625 10 3 19 15 or 238 . electrons for every 10 already present 9 . Section 23.2 Charging Objects by Induction Section 23.3 Coulomb’s Law P23.3 If each person has a mass of 70 kg and is (almost) composed of water, then each person contains N F H G I K J × F H G I K J F H G I K J ≅× 70 000 6 0 21 0 1 0 2 31 0 23 28 grams 18 grams mol molecules mol protons molecule protons . With an excess of 1% electrons over protons, each person has a charge q × = × 0 0 1 1 61 0 2 0 3 71 0 19 28 7 . . C C ej e j . So Fk qq r e × × 12 2 9 7 2 2 25 91 0 37 10 06 41 0 . . N N ~ 1 0 N 26 . This force is almost enough to lift a weight equal to that of the Earth: Mg 0 0 24 25 kg 9.8 m s N~10 N 22 6 . *P23.4 The force on one proton is F = kqq r e 2 away from the other proton. Its magnitude is 899 10 16 10
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