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665_Physics ProblemsTechnical Physics

665_Physics ProblemsTechnical Physics - Chapter 23 F 10.0...

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Chapter 23 5 P23.2 (a) N = F H G I K J × F H G I K J F H G I K J = × 10 0 6 02 10 47 2 62 10 23 24 . . . grams 107.87 grams mol atoms mol electrons atom (b) # . . electrons added C 1.60 10 C electron = = × × = × Q e 1 00 10 6 25 10 3 19 15 or 2 38 . electrons for every 10 already present 9 . Section 23.2 Charging Objects by Induction Section 23.3 Coulomb’s Law P23.3 If each person has a mass of 70 kg and is (almost) composed of water, then each person contains N F H G I K J × F H G I K J F H G I K J × 70 000 6 02 10 10 2 3 10 23 28 grams 18 grams mol molecules mol protons molecule protons . . . With an excess of 1% electrons over protons, each person has a charge q = × × = × 0 01 1 6 10 2 3 10 3 7 10 19 28 7 . . . . C C e je j . So F k q q r e = = × × = × 1 2 2 9 7 2 2 25 9 10 3 7 10 0 6 4 10 e j e j . . N N ~10 N 26 . This force is almost enough to lift a weight equal to that of the Earth: Mg = × = × 6 10 6 10 24 25 kg 9.8 m s N ~10 N 2 26 e j . *P23.4 The force on one proton is F = k q q r e 1 2 2 away from the other proton. Its magnitude is
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