668_Physics ProblemsTechnical Physics

# 668_Physics ProblemsTechnical Physics - 8 Electric Fields...

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8 Electric Fields Section 23.4 The Electric Field P23.13 For equilibrium, FF eg =− or qm g Ej ± ej . Thus, = mg q ± . (a) j j == × −× × mg q ± .. . ± . ± 911 10 980 160 10 558 10 31 19 11 kg m s C NC 2 e j (b) j j × × mg q ± . ± . ± 167 10 102 10 27 19 7 kg m s C 2 e j P23.14 F y = 0 : QE mg ±± jj +− = 0 ∴= = × = m QE g 24 0 10 610 149 6 . . . C N C ±ms grams 2 bg P23.15 The point is designated in the sketch. The magnitudes of the electric fields, E 1 , (due to the 250 10 6 . C charge) and E 2 (due to the 600 10 6 . × C charge) are E kq rd e 1 2 96 2 8 99 10 2 50 10 ×⋅ × Nm C C 22 e j (1) E r d e 2 2 2 8 99 10 6 00 10 100 × + . C m e j a f (2) FIG. P23.15 Equate the right sides of (1) and (2)
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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