669_Physics ProblemsTechnical Physics

# 669_Physics ProblemsTechnical Physics - 9 Chapter 23 P23.16...

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Chapter 23 9 P23.16 If we treat the concentrations as point charges, E j j E j j E E E + + = = × = × = = × = × = + = × k q r k q r e e 2 9 2 5 2 9 2 5 5 8 99 10 40 0 1 000 3 60 10 8 99 10 40 0 1 000 3 60 10 7 20 10 . . ± . ± . . ± . ± . N m C C m N C downward N m C C m N C downward N C downward 2 2 2 2 e j a f b g e j e j a f e j a f b g e j e j a f *P23.17 The first charge creates at the origin field k Q a e 2 to the right. Suppose the total field at the origin is to the right. Then q must be negative: k Q a k q a k Q a e e e 2 2 2 3 2 ± ± ± i i i + = a f e j q Q = − 9 . In the alternative, the total field at the origin is to the left: k Q a k q a k Q a e e e 2 2 2 9 2 ± ± ± i i i + = e j e j q Q = + 27 . x q +Q x = 0 FIG. P23.17 P23.18 (a) E k q r e 1 2 9 6 2 5 8 99 10 7 00 10 0 500 2 52 10 = = × × = × . . . . e je j a f N C E k q r E E E E E e x y 2 2 9 6 2 5 2 1 5 5 3 1 5 3 3 8 99 10 4 00 10 0 500 1 44 10 60 1 44 10 2 52 10 60 0 18 0 10 60 0 2 52 10 60 0 218 10 18 0 218 10 18 0 218 = = × × = × = °= × × °= × = − °= − × °= − × = × = . . . . cos . . cos . . sin . . sin . . ± ± . ± ± e je j a f N C N C N C N C kN C E i j i j FIG. P23.18 (b) F E i j i j i j = = × × = × = q 2 00 10 18 0 218 10 36 0 436 10 36 0 436 6
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