669_Physics ProblemsTechnical Physics

# 669_Physics ProblemsTechnical Physics - 9 Chapter 23 P23.16...

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Chapter 23 9 P23.16 If we treat the concentrations as point charges, Ej j j EE E + +− == × = × × = × =+= × k q r k q r e e 2 9 2 5 2 9 2 5 5 899 10 40 0 1000 360 10 40 0 720 10 . . ± . ± . . ± . ± . Nm C C m NC downward C m N C downward 22 ej af bg *P23.17 The first charge creates at the origin field kQ a e 2 to the right. Suppose the total field at the origin is to the right. Then q must be negative: a kq a a e e e 2 3 2 ±± ± ii i = qQ =− 9. In the alternative, the total field at the origin is to the left: a a a e e e 2 9 2 ± i = =+ 27 . x q +Q x = 0 FIG. P23.17 P23.18 (a) E r e 1 2 96 2 5 8 99 10 7 00 10 0500 252 10 ×× .. . . e j a f E r EEE EE e x y 2 2 2 5 21 55 3 1 53 3 8 99 10 4 00 10 144 10 60 1 44 10 2 52 10 60 0 18 0 10 60 0 2 52 10 60 0 218 10 18 0 218 10 18 0 218 ° = × × ° = × °=− × × × = . . cos . . cos . . sin . . sin . . . e j kNC Ei j i j FIG. P23.18 (b) F E ij × × = × = −− q 200 10 180 218 10 360 436 63 3 . . C N C N m N e j e je j P23.19 (a) j j 1 1 1 2 99 2 3 8 99 10 3 00 10 0100 270 10 = −= × r e ± . ± . ± e j a f ej e j i i i j 2 2 2 2 2 2 23 8 99 10 6 00 10 0300
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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