670_Physics ProblemsTechnical Physics

670_Physics ProblemsTechnical Physics - 10 Electric Fields...

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10 Electric Fields P23.20 (a) E k q r e = = × × = 2 9 6 2 8 99 10 2 00 10 1 12 14 400 . . . e je j a f N C E x = 0 and E y = °= × 2 14 400 26 6 1 29 10 4 b g sin . . N C so E j = × 1 29 10 4 . ± N C . FIG. P23.20 (b) F E j j = = − × × = × q 3 00 10 1 29 10 3 86 10 6 4 2 . . ± . ± e je j N P23.21 (a) E r r r i i j j = + + = + °+ ° + k q r k q r k q r k q a k q a k q a e e e e e e 1 1 2 1 2 2 2 2 3 3 2 3 2 2 2 2 3 2 45 0 45 0 4 ± ± ± ± ± cos . ± sin . ± b g b g e j b g E i j = + = ° 3 06 5 06 5 91 2 2 2 . ± . ± . k q a k q a k q a e e e at 58.8 (b) F E = = ° q k q a e 5 91 2 2 . at 58.8 P23.22 The electric field at any point x is E k q x a k q x a k q ax x a e e e = − − = a f a f c h a f e j 2 2 2 2 2 4 . When x is much, much greater than a , we find E a k q x e 4 3 b g . P23.23 (a) One of the charges creates at P a field E = + k Q n R x e 2 2 at an angle θ to the x -axis as shown. When all the charges produce field, for n > 1 , the components perpendicular to the x -axis add to zero. The total field is nk Q n R x k Qx R x e e b g e
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