670_Physics ProblemsTechnical Physics

670_Physics ProblemsTechnical Physics - 10 Electric Fields...

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10 Electric Fields P23.20 (a) E kq r e == ×× = 2 96 2 8 99 10 2 00 10 112 14 400 .. . ej e j a f NC E x = 0 and E y = × 2 14 400 26 6 1 29 10 4 bg sin . . N C so Ej 129 10 4 . ± NC . FIG. P23.20 (b) FE j j = = −× × = −− q 3 00 10 1 29 10 3 86 10 64 2 ± . ± e j N P23.21 (a) Er r r i i j j =++= + ° + ° + r r r a a a ee e ee e 1 1 2 1 2 2 2 2 3 3 2 3 22 2 23 2 45 0 45 0 4 ±±± ±± cos . ± sin . ± Eij =+= ° 306 506 591 2 . ± . ± . a a a e at 58.8 (b) ° q a e 2 2 . a t 5 8 . 8 P23.22 The electric field at any point x is E xa kq ax e = = af a f ch a f 2 4 . When x is much, much greater than a , we find E akq x e 4 3 . P23.23 (a) One of the charges creates at P a field E = + kQn Rx e at an angle θ to the x -axis as shown. When all the charges produce field, for n > 1 , the components perpendicular to the x -axis add to zero. The total field is nk Q n kQx e e ± cos ± i i 32 + = + . FIG. P23.23 (b) A circle of charge corresponds to letting
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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