20 Electric Fields*P23.53(a)Each ion moves in a quarter circle. The electric force causes the centripetal acceleration.Fma∑=qEmvR=2EmvqR=2(b)For the x-motion,vvaxxxfxixfi222=+−di022vaRxavRFmqEmxxx=−==22EmvqRx22. Similarly for the y-motion,Ry2avRqEmyy=22EmvqRy=22The magnitude of the field isEEmvqRxxy22+=°at 135 counterclockwise from the -axis .P23.54From the free-body diagram shown,Fy∑=0:Tcos..15 01 96 102°=×−N .SoT=×−203 102. N.From Fx∑=0 , we haveqET=°sin.15 0orqTE=°=×°×=−−sin..sin....15 0150100 10525 10525236NNCC Cejµ.FIG. P23.54P23.55(a)Let us sum force components to find
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .