Chapter 2325P23.66(a)The distance from each corner to the center of the square isLLL222FHGIKJ+FHGIKJ=.The distance from each positive charge to −Qis thenzL222+. Each positive charge exerts a force directed+q+q+q+qz–QL/2L/2xFIG. P23.66along the line joining qand −Q, of magnitudekQqzLe2+.The line of force makes an angle with the z-axis whose cosine isz2+The four charges together exert forces whose xand ycomponents add to zero, while thez-components add to Fk=−+4232kQqzeej±(b)For >>, the magnitude of this force is FLLzmazeezFHGIKJ=424223afTherefore, the object’s vertical acceleration is of the form azzω2with 233128==afmLmLee.Since the acceleration of the object is always oppositely directed to its excursion fromequilibrium and in magnitude proportional to it, the object will execute simple harmonicmotion with a period given by
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .