686_Physics ProblemsTechnical Physics

686_Physics ProblemsTechnical Physics - 26 Electric Fields...

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26 Electric Fields P23.68 The bowl exerts a normal force on each bead, directed along the radius line or at 60.0° above the horizontal. Consider the free-body diagram of the bead on the left: Fn m g y = sin . 60 0 0 , or n mg = ° sin . 60 0 . Also, FF n xe =− + °= cos . 60 0 0 , or kq R n mg mg e 2 2 60 0 60 0 3 = ° = cos . tan . . Thus, qR mg k e = F H G I K J 3 12 . n mg 60.0° F e FIG. P23.68 P23.69 (a) There are 7 terms which contribute: 3 are s away (along sides) 3 are 2 s away (face diagonals) and sin cos θθ == 1 2 1 is 3 s away (body diagonal) and sin φ = 1 3 . The component in each direction is the same by symmetry. Fi j k i j k =+ + L N M O Q P
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