692_Physics ProblemsTechnical Physics

692_Physics ProblemsTechnical Physics - 32 Gausss Law...

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32 Gauss’s Law Section 24.2 Gauss’s Law P24.9 (a) Φ E q = = +− + ×⋅ =− × in 22 C C CNm Nm C 0 12 6 5 00 9 00 27 0 84 0 885 10 689 10 .. . . µµµµ bg Φ E 689 . M NmC 2 (b) Since the net electric flux is negative, more lines enter than leave the surface. P24.10 (a) E kQ r e = 2 : 890 10 899 10 0750 2 9 2 . . . ×= × ej af Q But Q is negative since E points inward. Q × = − 556 10 556 8 n C (b) The negative charge has a spherically symmetric charge distribution. P24.11 Φ E q = in 0 Through S 1 Φ E QQ Q = −+ 2 00 Through S 2 Φ E = = 0 0 Through S 3 Φ E QQQ Q = −+− Through S 4 Φ E = 0 P24.12 (a) One-half of the total flux created by the charge q goes through the plane. Thus, ΦΦ EE qq ,, plane total == F H G I K J = 1 2 1 . (b) The square looks like an infinite plane to a charge very close to the surface. Hence,
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