695_Physics ProblemsTechnical Physics

695_Physics ProblemsTechnical Physics - Chapter 24 (a) E=...

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Chapter 24 35 P24.24 (a) E kQr a e == 3 0 (b) E a e ×× = 3 96 3 899 10 260 10 0100 0400 365 .. . . ej e j af a f kN C (c) E kQ r e = 2 2 146 . . e j a f MN C (d) E r e = 2 2 0600 649 . e j a f kN C The direction for each electric field is radially outward . *P24.25 mg qE q q QA F H G I K J = F H G I K J σ 22 00 Q A mg q = = × −× =− 2 2 8 85 10 0 01 9 8 07 10 248 0 12 6 . . . a f Cm 2 µ P24.26 (a) E k r e = 2 λ 360 10 2 8 99 10 2 40 0190 4 9 . . ×= × bg Q Q =+ × = + 913 10 913 7 . C n C (b) E = 0 *P24.27 The volume of the spherical shell is 4 3 025 020 319 10 33 2 π ... m m m 3 −= × . Its charge is ρ V × × × −−− 1 33 10 3 19 10 4 25 10 628 m C e j . The net charge inside a sphere containing the proton’s path as its equator is × = − × −− 60 10 4 25 10 1 02 10 98 7 C C . The electric field is radially inward with magnitude
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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