40 Gauss’s LawP24.45The charge divides equally between the identical spheres, with charge Q2on each. Then they repellike point charges at their centers:FkQ QLRRkQLRee=++=+=×⋅×=−2242899 10600 10012002229622bgafafej....NmCC mN22.P24.46The electric field on the surface of a conductor varies inversely with the radius of curvature of thesurface. Thus, the field is most intense where the radius of curvature is smallest and vice-versa. Thelocal charge density and the electric field intensity are related byE=∈σ0or=∈0E.(a)Where the radius of curvature is the greatest,=∈=×⋅×=−01248 85 102 80 10248Emin2CNmNCnCmej.(b)Where the radius of curvature is the smallest,=∈=×⋅×=−01248 85 105 60 10496Emaxn2ej.P24.47(a)Inside surface: consider a cylindrical surface within the metal. Since Einside the conductingshell is zero, the total charge inside the gaussian surface must be zero, so the inside
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