704_Physics ProblemsTechnical Physics

704_Physics ProblemsTechnical Physics - 44 Gausss Law...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
44 Gauss’s Law *P24.59 The vertical velocity component of the moving charge increases according to m dv dt F y y = m dv dx dx dt qE y y = . Now dx dt v x = has the nearly constant value v . So dv q mv Edx yy = vd v q mv v y y == zz −∞ 0 . v x v y x y d q v 0 θ Q FIG. P24.59 The radially outward compnent of the electric field varies along the x axis, but is described by EdA E ddx Q −∞ −∞ 2 0 π bg . So Q d y −∞ z = 2 0 and v qQ mv d y = 2 0 . The angle of deflection is described by tan v v qQ dmv y 2 0 2 = tan 1 0 2 2 qQ dmv . P24.60 First, consider the field at distance rR < from the center of a uniform sphere of positive charge Qe =+ with radius R . 4 2 00 4 3 3 4 3 3 0 ρ rE q Ve R r ej = = = + F H G I K J in so E e R = F H G I K J 4 0 3 r directed outward (a) The force exerted on a point charge qe =− located at distance r from the center is then Fq
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

Ask a homework question - tutors are online