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713_Physics ProblemsTechnical Physics

# 713_Physics ProblemsTechnical Physics - Chapter 25 P25.2 53...

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Chapter 25 53 P25.2 ∆∆ KqV = 737 10 115 17 . ×= q af q 641 10 19 . C P25.3 (a) Energy of the proton-field system is conserved as the proton moves from high to low potential, which can be defined for this problem as moving from 120 V down to 0 V. KU E K U ii f f ++ = + mech 00 1 2 0 2 = + qV mv p 160 10 120 11 2 167 10 19 27 2 .. × F H G I K J −− C V J 1 V C kg ej v p v p 152 10 5 m s (b) The electron will gain speed in moving the other way, from V i = 0 to V f = 120 V : f f mech 000 1 2 2 ++= + mv qV e 0 1 2 9 11 10 1 60 10 120 31 2 19 + × kg C J C e j bg v e v e 649 10 6 m s P25.4 WKq V == 0 1 2 9 11 10 4 20 10 1 60 10 31 5 2 19 −× × = × . kg m s C e j V From which, V =− 0502 V . Section 25.2 Potential Difference in a Uniform Electric Field P25.5 (a) We follow the path from (0, 0) to (20.0 cm, 0) to (20.0 cm, 50.0 cm). U (work done)
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