715_Physics ProblemsTechnical Physics

715_Physics ProblemsTechnical Physics - Chapter 25 (c) d2x...

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Chapter 25 55 (c) The block’s equation of motion is Fk x Q E m dx dt x =− + = 2 2 . Let ′= − xx QE k , or QE k =′ + , so the equation of motion becomes: −′ + F H G I K J += + kx QE k QE m dxQ E k dt 2 2 bg , or dt k m x 2 2 F H G I K J . This is the equation for simple harmonic motion ax x ω 2 with = k m . The period of the motion is then T m k == 2 2 π . (d) KU U E se i f ++ + =++ mech 000 0 1 2 2 2 ++− =+ = µ k k mgx kx QEx x QE mg k max max max max P25.12 For the entire motion, yyv t a t fiy i y −= + 1 2 2 00 1 2 2 vt a t iy so a v t y i 2 Fm a yy = : −−= mg qE mv t i 2 E m q v t g i F H G I K J 2 and Ej F H G I K J m q v t g i 2 ± . For the upward flight: vv a y y yf yi y f i 22 2 di 02 2 0 2 =+− F H G I K J v v t y i i max and yv t i max = 1 4 Vd m q v t gy m q v t gv t V y i y i i F H G I K J F H G I K J F H G I K J = × F H G I K J L N M O Q P = z Ey 0 0 6 1 4 200 10 2201 410 980 1 4 20 1 4 10 40 2 max max . . . .. . . kg 5.00 C ms s s kV 2 af
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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