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718_Physics ProblemsTechnical Physics

718_Physics ProblemsTechnical Physics - 58 Electric...

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58 Electric Potential P25.21 U q V q V q V q q r q r q r e = + + = F H G I K J + + F H G I K J 4 1 4 2 4 3 4 0 1 1 2 2 3 3 1 4 π U U e e = × × + + + F H G G I K J J = 10 0 10 8 99 10 1 0 600 1 0 150 1 0 600 0 150 8 95 6 2 9 2 2 . . . . . . . C N m C m m m m J 2 2 e j e j a f a f P25.22 (a) V k q r k q r k q r e e e = + = F H G I K J 1 1 2 2 2 V V = × × + F H G G I K J J = × = 2 8 99 10 2 00 10 1 00 0 500 3 22 10 32 2 9 6 2 2 4 . . . . . . N m C C m m V kV 2 2 e je j a f a f FIG. P25.22 (b) U qV = = − × × = × 3 00 10 3 22 10 9 65 10 6 4 2 . . . C J C J e je j P25.23 U U U U U U U U U U U U U k Q s k Q s k Q s U k Q s k Q s e e e e e = + + + = + + + + + + = + + + F H G I K J + + + F H G I K J = + F H G I K J = 1 2 3 4 12 13 23 14 24 34 2 2 2 2 2 0 0 1 2 1 1 1 2 1 4 2 2 5 41 b g b g . FIG. P25.23 An alternate way to get the term 4 2 2 + F H G I K J is to recognize that there are 4 side pairs and 2 face diagonal pairs. P25.24 Each charge creates equal potential at the center. The total potential is: V k q R k q
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