722_Physics ProblemsTechnical Physics

722_Physics ProblemsTechnical Physics - 62 Electric...

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62 Electric Potential P25.33 Using conservation of energy we have: keQ r kqQ r mv e e 12 2 1 2 =+ which gives: v mr r e =− F H G I K J 2 11 or v = ×⋅ × × F H G I K J −− 2 8 99 10 1 60 10 10 911 10 1 00300 1 00200 91 9 9 31 af ej e j e j .. . Nm C C C kg m m 22 . Thus, v 726 10 6 . m s . P25.34 U kqq r ei j ij = , summed over all pairs of ij , bg where . Uk qq b a b a ab q U e e = + ++ + + + + L N M M O Q P P = −+++− L N M O Q P × L N M O Q P 3 2 32 3 2 2 2 0400 6 0200 6 2 3 0447 4 8 99 10 6 00 10 4 4 1 396 2 96 2 b gb g bgbg bg bg b g e j ...... ... J FIG. P25.34 P25.35 Each charge moves off on its diagonal line. All charges have equal speeds. KU kq L L mv L L L mv v mL if ee e e += + ++= F H G I K J + F H G I K J = F H G I K J ∑∑ afaf 0 42 2 4 1 2 4 2 2 2 1 2 2 1 1 8 2 2 2 2 P25.36 A cube has 12 edges and 6 faces. Consequently, there are 12 edge pairs separated by s , 261 2 ×= face diagonal pairs separated by 2 s and 4 interior diagonal pairs separated
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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