729_Physics ProblemsTechnical Physics

729_Physics ProblemsTechnical Physics - Chapter 25 P25.60...

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Chapter 25 69 P25.60 The positive plate by itself creates a field E = = × ×⋅ = σ 2 36 0 10 2 8 85 10 203 0 9 12 . . . Cm CNm kN C 2 22 ej away from the + plate. The negative plate by itself creates the same size field and between the plates it is in the same direction. Together the plates create a uniform field 407 . kN C in the space between. (a) Take V = 0 at the negative plate. The potential at the positive plate is then Vd x −= z 04 0 7 0 12 0 . . kN C cm bg . The potential difference between the plates is V = 407 10 0120 488 3 .. NC m V a f . (b) 1 2 1 2 mv qV mv qV if + F H G I K J =+ F H G I K J qV mv f = = × −− 160 10 1 2 781 10 19 2 17 C V J a f (c) v f = 306 km s (d) vv a xx fi 2 di 306 10 0 2 0120 390 10 5 2 11 . ×= + ms m 2 a f a a (e) Fm a == × × = × 1 67 10 3 90 10 6 51 10 27 11 16 . kg m s N 2 e j (f) E F q × × = 651 10
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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