735_Physics ProblemsTechnical Physics

735_Physics ProblemsTechnical Physics - Chapter 25 *P25.73...

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Chapter 25 75 *P25.73 (a) The whole charge on the cube is q = −− 100 10 0 1 10 6 3 7 Cm m C 3 ej af . . Divide up the cube into 64 or more elements. The little cube labeled a creates at P potential kq e 64 6 25 1 25 1 25 10 222 2 ... ++ m . The others in the horizontal row behind it contribute e 64 10 1 875 3125 1 11 25 3 125 1 13 75 3 125 2 + + + + + F H G I K J m .. . The little cubes in the rows containing b and c add 2 64 10 6 25 1 25 3 75 8 75 15 625 11 25 15 625 13 75 15 625 2 12 2 2 2 e + + L N M O Q P m e j . . and the bits in row d make potential at P e 64 10 6 25 28 125 13 75 28 125 2 2 2 + + L N M O Q P m e j . a b d c P 1.25 cm FIG. P25.73 The whole potential at P is 89876 10 10 64 10 1580190 4 8876 97 2 . . ×× = Nm C C m V 2 2 bg . If we use more subdivisions of the large cube, we get the same answer to four digits. (b) A sphere centered at the same point would create potential r e = = 10 8988 1 . N m C m V 2 2 , larger by 112 V . ANSWERS TO EVEN PROBLEMS
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