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740_Physics ProblemsTechnical Physics

# 740_Physics ProblemsTechnical Physics - 80 Capacitance and...

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80 Capacitance and Dielectrics SOLUTIONS TO PROBLEMS Section 26.1 Definition of Capacitance P26.1 (a) Q C V = = × = × = 4 00 10 12 0 4 80 10 48 0 6 5 . . . . F V C C e j a f µ (b) Q C V = = × = × = 4 00 10 1 50 6 00 10 6 00 6 6 . . . . F V C C e j a f µ P26.2 (a) C Q V = = × = × = 10 0 10 1 00 10 1 00 6 6 . . . C 10.0 V F F µ (b) V Q C = = × × = 100 10 10 100 6 6 C 1.00 F V Section 26.2 Calculating Capacitance P26.3 E k q r e = 2 : q = × × = 4 90 10 0 210 8 99 10 0 240 4 2 9 . . . . N C m N m C C 2 2 e j a f e j µ (a) σ π µ = = × = q A 0 240 10 4 0 120 1 33 6 2 . . . a f C m 2 (b) C r = = × = 4 4 8 85 10 0 120 13 3 0 12 π π . . . e j a f pF P26.4 (a) C R = 4 0 π R C k C e = = = × × = 4 8 99 10 1 00 10 8 99 0 9 12 π . . . N m C F mm 2 2 e je j (b) C R = = × × = 4 4 8 85 10 2 00 10 0 222 0 12 3 π π .
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