745_Physics ProblemsTechnical Physics

# 745_Physics ProblemsTechnical Physics - Chapter 26 P26.21(a...

This preview shows page 1. Sign up to view the full content.

Chapter 26 85 P26.21 (a) 11 15 0 1 300 C s =+ .. C C C s p eq = =+= F H G I K J = 250 250 600 850 1 850 1 20 0 596 1 . ... . F F F F F µ µµ (b) QCV == = 150 895 . V C bg af on 20 0 . F V Q C = −= = 89 5 447 15 0 4 47 10 53 600 1053 632 . . . . C 20.0 F V V F V C on 6.00 F 89 5 63 2 26 3 . C on 15 0 and 300 FIG. P26.21 *P26.22 (a) Capacitors 2 and 3 are in parallel and present equivalent capacitance 6 C . This is in series with capacitor 1, so the battery sees capacitance 1 3 1 6 2 1 CC C + L N M O Q P = . (b) If they were initially unchanged, C 1 stores the same charge as C 2 and C 3 together. With greater capacitance, C 3 stores more charge than C 2 . Then QQQ 132 >> . (c) The 23 || equivalent capacitor stores the same charge as C 1 . Since it has greater capacitance, V Q C = implies that it has smaller potential difference across it than C 1 . In parallel with each other, C 2 and C 3 have equal voltages: ∆∆∆
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Ask a homework question - tutors are online