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747_Physics ProblemsTechnical Physics

747_Physics ProblemsTechnical Physics - Chapter 26 P26.28 a...

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Chapter 26 87 P26.28 Q C V eq eq = = × = × a f e j a f 6 04 10 60 0 3 62 10 6 4 . . . F V C Q Q p eq 1 = , so V Q C p eq p 1 1 4 6 3 62 10 8 66 10 41 8 = = × × = . . . C F V Q C V p 3 3 1 6 2 00 10 41 8 = = × = e j e j a f . . F V 83.6 C µ P26.29 C C s p = + F H G I K J = = + + = 1 5 00 1 7 00 2 92 2 92 4 00 6 00 12 9 1 . . . . . . . F F µ µ FIG. P26.29 *P26.30 According to the suggestion, the combination of capacitors shown is equivalent to Then 1 1 1 1 0 0 0 0 0 0 0 0 C C C C C C C C C C C C C = + + + = + + + + + b g C C C C C C C C C C C C C C 0 0 2 2 0 2 0 0 2 0 0 2 0 2 2 3 2 2 0 2 4 4 2 4 + = + + = = ± + e j Only the positive root is physical C C = 0 2 3 1 e j FIG. P26.30 Section 26.4 Energy Stored in a Charged Capacitor
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