92 Capacitance and DielectricsP26.48(a)CCAd==∈=×××=−−−κ001243173 8 85 101 00 100100 10153afejej....mmnF2(b)The battery delivers the free chargeQCV×=−∆af153 101201849.F VnC.(c)The surface density of free charge isσ××=×−−−QA18 4 1010184 10944..C1.00mCm22.The surface density of polarization charge isσσp=−FHGIKJFHGIKJ−1111173183 104. Cm2.(d)We have EE=0and EVd0=∆; hence,EVd×=−∆12 0100 106944..V173mVm.P26.49The given combination of capacitors is equivalent to the circuit diagramshown to the right.Put charge Qon point A. Then,QVVVABBCCD===40 010 040 0...Fµµµbgbgbg∆∆∆.FIG. P26.49So, VVVBCABCD44, and the center capacitor will break down first, at ∆VBC=15 0. V . Whenthis occurs,∆∆∆VVVABCDBC=14375bgVand VVADABBCCD=++=++=150225..V VV.Section 26.6Electric Dipole in an Electric FieldP26.50(a)The displacement from negative to positive charge is
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .