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753_Physics ProblemsTechnical Physics

# 753_Physics ProblemsTechnical Physics - Chapter 26(c e j e...

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Chapter 26 93 (c) U = − = − + × × p E i j i j 9 10 8 40 10 7 80 4 90 10 12 3 . ± . ± . ± . ± e j e j C m N C U = + × = 71 0 41 2 10 112 9 . . a f J nJ (d) p = + × = × 9 10 8 40 10 12 4 10 2 2 12 12 . . . a f a f C m C m E p E = + × = × = = = − = 7 80 4 90 10 9 21 10 114 114 228 2 2 3 3 . . . max min max min a f a f N C N C nJ, nJ nJ U U U U P26.51 (a) Let x represent the coordinate of the negative charge. Then x a + 2 cos θ is the coordinate of the positive charge. The force on the negative charge is F i = − qE x a f ± . The force on the positive charge is F i i i + = + + + qE x a qE x q dE dx a 2 2 cos ± ± cos ± θ θ a f a f a f . E θ p F + F - FIG. P26.51(a) The force on the dipole is altogether F F F i i = + = = + q dE dx a p dE dx 2 cos ± cos ± θ θ a f . (b) The balloon creates field along the x -axis of k q x e 2 ± i . Thus, dE dx k q x e = 2 3 a f . At x = 16 0 . cm, dE dx = × × = 2 8 99 10
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