755_Physics ProblemsTechnical Physics

755_Physics ProblemsTechnical Physics - Chapter 26 *P26.55...

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Chapter 26 95 *P26.55 (a) Each face of P 2 carries charge, so the three-plate system is equivalent to P 1 P 2 P 2 P 3 Each capacitor by itself has capacitance C A d = = ×× ⋅× = −− κ 0 12 4 3 1 8 85 10 7 5 10 119 10 558 .. . . C m Nm m pF 22 2 ej . Then equivalent capacitance =+= 5 58 5 58 11 2 . p F . (b) QCVCV × = ∆∆ 11 2 10 12 134 12 . F V p C a f (c) Now P 3 has charge on two surfaces and in effect three capacitors are in parallel: C == 3 5 58 16 7 pF pF bg . (d) Only one face of P 4 carries charge: QCV × = 558 10 669 12 F12 V pC a f . *P26.56 From the example about a cylindrical capacitor, VV k b a V V ba e b b −= × × =− × × −× = × 2 345 2 8 99 10 1 40 10 12 2 8 99 1 4 10 500 15643 10 3 45 10 1 56 10 1 89 10 96 3 5 55 5 λ ln l n l n . . kV Nm C C m m 0.024 m JC V V V V e j a f *P26.57 Imagine the center plate is split along its midplane and pulled apart.
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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